Answer
$r_{2}=Rr_{1}\div({r_{1}-R})$
Work Step by Step
$R(r_{1}+r_{2})=r_{1}r_{2}$
$Rr_{1}+Rr_{2}=r_{1}r_{2}$
$Rr_{1}=r_{1}r_{2}-Rr_{2}$
$Rr_{1}=r_{2}(r_{1}-R)$
$r_{2}=Rr_{1}\div({r_{1}-R})$
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 1 - Expressions, Equations, and Inequalities - 1-4 Solving Equations - Practice and Problem-Solving Exercises - Page 31: 51
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