Answer
$43, 45, 47, 49$
Work Step by Step
Start with the equation;
$(x)+(x+2)+(x+4)+(x+6)=184$
where $x$ is the smallest odd number among the four.
We have a base number $x$ and 3 consecutive odds above it.
Combining like terms brings us to
$4x=172$.
Divide both sides by $4$, and we find
$x=43$.
The three consecutive odd integers above it are $45, 47,$ and $49$