Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Section R.2 - Fractions - Exercise Set - Page R-17: 77

Answer

$\frac{17}{18}$

Work Step by Step

1. Find LCD of fractions: 18 2. Write as equivalent fractions with 18 as common denominator: $\frac{2}{3} - \frac{5}{9} + \frac{5}{6} = \frac{2*6}{3*6} - \frac{5*2}{9*2} + \frac{5*3}{6*3} = \frac{12}{18} - \frac{10}{18} + \frac{15}{18} = \frac{12 - 10 + 15}{18} = \frac{17}{18}$
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