Answer
$$x=−4±2\sqrt5$$
Work Step by Step
Using the quadratic formula, we obtain:
$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
$$x=\frac{-8\pm \sqrt{(8)^2-4(-4)(1)}}{2(1)}$$
$$x=−4±2\sqrt5$$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 111: 73
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