Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 111: 95

Answer

$$x=-2.200,-.290$$

Work Step by Step

Using the quadratic formula, we obtain: $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ $$x=\frac{-.31.55\pm \sqrt{(31.55)^2-4(12.67)(8.09)}}{2(12.67)}$$ $$x=-2.200,-.290$$
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