Answer
${6-\sqrt {11}, 6+\sqrt {11}}$
Work Step by Step
$(y-5)^2=2y$
$y^2-10y+25=2y$
$y^2-12y+25=0$
$y^2-12y+36=11$
$(y-6)^2=11$
$(y-6)=\sqrt {11} or -\sqrt {11}$
$y=6+\sqrt {11}$ or $6-\sqrt {11}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 111: 87
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