Answer
$\frac{4}{y+4}$
Work Step by Step
$\frac{y^2+8y+16}{2y-4}*\frac{8y-16}{(y+4)^3}=\frac{(y+4)^2}{2y-4}*\frac{4(2y-4)}{(y+4)^3}=$$\frac{4}{y+4}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - Chapter Test - Page 65: 16
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