Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - Chapter Test - Page 65: 7

Answer

See the explanation

Work Step by Step

a. $9z\sqrt {8z}-3\sqrt {2z^3}$ $=18z\sqrt {2z} - 3z\sqrt {2z}$ $=(18z-3z)\sqrt {2z}$ $=15z\sqrt {2z} $ b.$(4x^{\frac{3}{5}})(x^{\frac{1}{3}})$ $=4^{\frac{3}{5} + \frac{1}{3}}$ $=4x^{\frac{14}{15}}$ c. $\sqrt[3] {\frac{16}{x^5}}=\sqrt[3] {\frac{2\times 2^3}{x^2\times x^3}}$ $=\sqrt[3] {\frac{2}{x^2}} \times \sqrt[3] {\frac{2^3}{x^3}}$ $=\sqrt[3] {\frac{2}{x^2}} \times \frac{2}{x}$ $=\frac{2}{x} \sqrt[3]{\frac{2}{x^2}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.