Answer
See the explanation
Work Step by Step
a. $3z^2(2z^3)^2$
$=3z^2(2^2z^6)$
$=12z^8$
b. $(u-2)^{-4}(u-2)^{-3}$
$=(u-2)^{-7}$
$= \frac{1}{(u-2)^7}$
c. $\left(\frac{x^{-2}y^2}{3}\right)^{-1}$
$=\frac{x^2y^{-2}}{3^{-1}}$
$=\frac{3x^2}{y^2}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - Chapter Test - Page 65: 6
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