Answer
$3\sqrt[3] {16}$
Work Step by Step
$\frac{12}{\sqrt[3] 4}=\frac{12}{\sqrt[3] 4}\frac{\sqrt[3] {4^2}}{\sqrt[3] {4^2}}=\frac{12\sqrt[3] {4^2}}{\sqrt[3] {4^3}}=\frac{4(3)\sqrt[3] {4^2}}{4}=3\sqrt[3] {4^2}=3\sqrt[3] {16}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - Review Exercises - Page 63: 52
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