Answer
$2+\sqrt 3$
Work Step by Step
$\frac{1}{2-\sqrt 3}=\frac{1}{2-\sqrt 3}\frac{2+\sqrt 3}{2+\sqrt 3}=\frac{1(2+\sqrt 3)}{2(2)+2(\sqrt x3)-\sqrt 3(2)-\sqrt 3(\sqrt 3)}=\frac{2+\sqrt 3}{4-(\sqrt 3)^2}=\frac{2+\sqrt 3}{4-3}=\frac{2+\sqrt 3}{1}=2+\sqrt 3$
