Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - Review Exercises - Page 63: 66

Answer

$-2y^2+11y-8$

Work Step by Step

$8y-[2y^2-(3y-8)]=8y-[2y^2-3y-(-8)]=8y-[2y^2-3y+8]=8y-2y^2-(-3y)-8=8y-2y^2+3y-8=(8+3)y-2y^2-8=-2y^2+11y-8$
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