Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.1 - Solving Simple Equations - Exercises - Page 10: 62

Answer

$\dfrac{5\text{ L}}{\text{min}}=\dfrac{300\text{ L}}{\text{hour}}$

Work Step by Step

There are $60$ minutes in one hour. Thus, multiply both the numerator and the denominator by $60$ to obtain: $$\begin{align*} \frac{5\text{ L}}{\text{min}}&=\frac{60\cdot 5\text{ L}}{60\cdot \text{ min}}\\ \\&=\frac{300\text{ L}}{60\text{ min}}\\ \\&=\frac{300\text{ L}}{\text{hour}} \end{align*}$$
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