Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.3 - Solving Equations with Variables on Both Sides - Exercises - Page 24: 31

Answer

$x=10$ $\text{Surface area}\approx196.35\,cm^{2}$ $\text{Volume}\approx196.35\,cm^{3}$

Work Step by Step

$\text{Surface area}=2\pi r^{2}+2\pi rh$ $\text{Volume}=\pi r^{2}h$ Here, $r$ is the radius and $h$ is the height of the cylinder. Given: $\text{Surface area}=\text{Volume}$ $\implies 2\pi r^{2}+2\pi r h=\pi r^{2}h$ Dividing both sides of the above equation by $\pi r$, we get $2r+2h=rh$ $r=2.5\,cm$ $h=x\,cm$ Substituting these values, we have $2(2.5)+2x=2.5x$ $\implies 5+2x=2.5x$ $\implies 5=2.5x-2x=0.5x$ $x=\frac{5}{0.5}=10$ $\text{Surface area}=2\pi(2.5)^{2}+2\pi(2.5)(10)$ $\approx196.35\,cm^{2}$ $\text{Volume}=\pi(2.5)^{2}(10)\approx196.35\,cm^{3}$
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