Chapter 1 - Solving Linear Equations - 1.3 - Solving Equations with Variables on Both Sides - Exercises - Page 24: 37

11 and 12.

Let the two consecutive integers be $n$ and $n+1$. From the statement given in the question, we can write $2(n+1)=3n-9$. $\implies 2n+2=3n-9$ $\implies 2+9=3n-2n$ or $n=11$. So, the integers are $11$ and $n+1=11+1=12$.