Answer
$p=2$
Work Step by Step
$\frac{2}{3}p=\frac{1}{2}p+\frac{1}{3}$ $\longrightarrow$ addition property of equality
$\frac{2}{3}p-\frac{1}{2}p=\frac{1}{2}p+\frac{1}{3}-\frac{1}{2}p$ $\longrightarrow$ combine like terms
$\frac{1}{6}p=\frac{1}{3}$ $\longrightarrow$ multiplication property of equality
$\frac{1}{6}p\times6=\frac{1}{3}\times6$ $\longrightarrow$ simplify
$p=2$
