Answer
{$-1$}
Work Step by Step
$x(2x-3)=(2x+1)(x-4)$ Distribute, multiply and combine like terms.
$2x^2-3x=2x^2-8x+x-4$
$2x^2-2x^2-3x=2x^2-2x^2-7x-4$ Subtract $2x^2$ from both sides.
$-3x+7x=-7x+7x-4$ Add $7x$ to both sides.
$4x=-4$
$\frac{4}{4}x=\frac{-4}{4}$ Divide both sides by 4.
$x=-1$
The solution is {$-1$}