Answer
$\mathrm{k}=\pm 4$
Work Step by Step
For a repeated real solution, the discriminant must be zero.
$\mathrm{b}^{2}-4\mathrm{a}\mathrm{c}=0$
$(-\mathrm{k})^{2}-4(1)(4)=0$
$\mathrm{k}^{2}=16$
$\mathrm{k}=\pm 4$
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