Answer
$x^3-6x^2+12x-8$
Work Step by Step
$(x-2)^3$
The cube of the difference of two terms is written as: $a^3 – 3a^2b + 3ab^2 – b^3$
After substituting:
$x^3-3(x^2*2)+3(x)(2)^2-(2)^3=$
$x^3-6x^2+12x-8$
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