Answer
$27x^3-54x^2+36x-8$
Work Step by Step
RECALL:
The formula for the cube of a binomial $a-b$ is
$(a-b)^3=a^3-3a^2b+3ab^2-b^3$
Use the formula above with $a=3x$ and $b=2$ to obtain:
$(3x-2)^3
\\= (3x)^3 - 3(3x)^2(2) + 3(3x)(2^2) - 2^3
\\=27x^3 - 3(9x^2)(2)+3(3x)(4)-8
\\=27x^3-54x^2+36x-8$
