College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Review Exercises - Page 76: 107

Answer

$-\dfrac{\sqrt[3]{50p}}{5p}$

Work Step by Step

The given expression, $ -\sqrt[3]{\dfrac{2}{5p^2}} ,$ simplifies to \begin{array}{l}\require{cancel} -\sqrt[3]{\dfrac{2}{5p^2}\cdot\dfrac{5^2p}{5^2p}} \\\\= -\sqrt[3]{\dfrac{2(25p)}{5^3p^3}} \\\\= -\sqrt[3]{\dfrac{50p}{(5p)^3}} \\\\= -\dfrac{\sqrt[3]{50p}}{\sqrt[3]{(5p)^3}} \\\\= -\dfrac{\sqrt[3]{50p}}{5p} .\end{array}
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