College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Review Exercises - Page 76: 90

Answer

$-\dfrac{16p^{7}}{q}$

Work Step by Step

Using the laws of exponents, the given expression, $ (8p^2q^3)(-2p^5q^{-4}) ,$ simplifies to \begin{array}{l}\require{cancel} 8(-2)p^{2+5}q^{3+(-4)} \\\\= -16p^{7}q^{-1} \\\\= \dfrac{-16p^{7}}{q^1} \\\\= -\dfrac{16p^{7}}{q} .\end{array}
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