College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises - Page 40: 90

Answer

$(6a+5)^2$

Work Step by Step

The two numbers whose product is $ac= 36(25)=900 $ and whose sum is $b= 60 $ are $\{ 30,30 \}$. Using these two numbers to decompose the middle term of the expression, $ 36a^2+60a+25 ,$ then the factored form is \begin{array}{l}\require{cancel} 36a^2+30a+30a+25 \\\\= (36a^2+30a)+(30a+25) \\\\= 6a(6a+5)+5(6a+5) \\\\= (6a+5)(6a+5) \\\\= (6a+5)^2 .\end{array}
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