College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises - Page 40: 98

Answer

$(6p+5q)(36p^2-30pq+25q^2)$

Work Step by Step

Using $a^3\pm b^3=(a\pm b)(a^2\mp ab+b^2)$ or the factoring of two cubes, the factored form of the given expression, $ 216p^3+125q^3 ,$ is \begin{array}{l}\require{cancel} (6p+5q)[(6p)^2-6p(5q)+(5q)^2] \\\\= (6p+5q)(36p^2-30pq+25q^2) .\end{array}
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