College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.5 - Rational Expressions - R.5 Exercises - Page 47: 28

Answer

$\frac{7}{y}$

Work Step by Step

Given. $\frac{y^3+y^2}{7}\cdot\frac{49}{y^4+y^3}$ Factor each rational expression. $=\frac{y^2(y+1)}{7}\cdot\frac{7\cdot7}{y^3(y+1)}$ Cancel the common factors then multiply. $=\frac{7}{y}$
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