Answer
$\{x|x\ne-2,-3\}$
Work Step by Step
In this rational expression, the solution to the denominator cannot be zero. Solve the denominator for x by factoring and setting each factor to 0. These answers are restricted from the domain.
$x^2+5x+6=0$
$(x+2)(x+3)=0$
$x=-2$ or $x=-3$
Put the domain in set notation.
$\{x|x\ne-2,-3\}$
