College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.5 - Rational Expressions - R.5 Exercises - Page 47: 33

Answer

$\dfrac{m+6}{m+3}$

Work Step by Step

The given expression, $ \dfrac{m^2+3m+2}{m^2+5m+4}\div\dfrac{m^2+5m+6}{m^2+10m+24} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{m^2+3m+2}{m^2+5m+4}\cdot\dfrac{m^2+10m+24}{m^2+5m+6} \\\\= \dfrac{(m+2)(m+1)}{(m+4)(m+1)}\cdot\dfrac{(m+4)(m+6)}{(m+2)(m+3)} \\\\= \dfrac{(\cancel{m+2})(\cancel{m+1})}{(\cancel{m+4})(\cancel{m+1})}\cdot\dfrac{(\cancel{m+4})(m+6)}{(\cancel{m+2})(m+3)} \\\\= \dfrac{m+6}{m+3} .\end{array}
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