College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.6 - Rational Exponents - R.6 Exercises - Page 57: 70

Answer

$\dfrac{10}{a^{1/8}\cdot b^{3/2}}$

Work Step by Step

$\begin{array}{ l c } =\left(\dfrac{25^{4/8} \cdot a^{3/8}}{b^{2/8}}\right)\left(\dfrac{4^{2/4} \cdot b^{-5/4}}{a^{2/4}}\right) & \begin{array}{l} \mathrm{Apply\ the\ rule}\\ \left(\dfrac{a^{b}}{b^{d}}\right)^{n} =\dfrac{a^{bn}}{b^{dn}} \end{array}\\ & \\ =\left(\dfrac{25^{1/2} \cdot a^{3/8}}{b^{1/4}}\right)\left(\dfrac{4^{1/2}\cdot b^{-5/4}}{a^{1/2} }\right) & \mathrm{Reduce\ the\ fraction\ in\ the\ exponent}\\ & \\ =\left(\dfrac{25^{1/2} \cdot a^{3/8}}{b^{1/4}}\right)\left(\dfrac{4^{1/2}}{a^{1/2} \cdot b^{5/4}}\right) & \text{Use the rule }a^{-n}=\dfrac{1}{a^n}.\\\ & \\ =\left(\dfrac{\sqrt{25} \cdot a^{3/8}}{b^{1/4}}\right)\left(\dfrac{\sqrt{4}}{a^{1/2} \cdot b^{5/4}}\right) & \begin{array}{l} \mathrm{For\ numerical\ expressions,\ }\\ \mathrm{apply\ the\ rule} \ a^{1/n} =\sqrt{a}. \end{array}\\ & \\ =\left(\dfrac{5\cdot a^{3/8}}{b^{1/4}}\right)\left(\dfrac{2}{a^{1/2} \cdot b^{5/4}}\right) & \mathrm{Simplify\ the\ numerical\ expressions.}\\ & \\ =\dfrac{10a^{3/8}}{a^{1/2}\cdot b^{1/4} \cdot b^{5/4}} & \begin{array}{l} \mathrm{Multiply\ the\ rational\ expressions}\\ \left(\dfrac{a}{b}\right)\left(\dfrac{c}{d}\right) =\dfrac{ac}{bd} \end{array}\\ & \\ =\dfrac{10a^{3/8}}{a^{4/8}\left(b^{1/4+5/4}\right)} & \begin{array}{l} \mathrm{Rewrite} \ 1/2\ \mathrm{as} \ 4/8\mathrm{\ }\\ \mathrm{apply\ the\ rule} \ a^{b} \cdot a^{c} =a^{b+c} \end{array}\\ & \\ =\dfrac{10}{\left(a^{4/8-3/8}\right)\left(b^{1/4+5/4}\right)} & \begin{array}{l} \mathrm{Apply\ the\ rule}\\ \dfrac{a^{b}}{a^{c}} =\dfrac{1}{a^{c-b}} \end{array}\\ & \\ =\dfrac{10}{a^{1/8} \cdot b^{6/4}} & \mathrm{Simplify.}\\ & \\ =\dfrac{10}{a^{1/8} \cdot b^{3/2}} & \end{array}$
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