College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.6 - Rational Exponents - R.6 Exercises - Page 57: 71

Answer

$p^2$

Work Step by Step

$\begin{array}{|l|c|} \hline =\dfrac{p^{( 1/5+7/10+1/2)}}{\left( p^{3}\right)^{-1/5}} & \begin{array}{l} \mathrm{Apply\ the\ rule}\\ a^{m} \cdot a^{n} =a^{m+n} \end{array}\\ & \\ \hline =\dfrac{p^{( 2/10+7/10+5/10)}}{\left( p^{3}\right)^{-1/5}} & \begin{array}{l} \mathrm{The\ LCD\ of\ the\ fractional}\\ \mathrm{exponents\ is} \ \mathrm{ten} .\\ \dfrac{1}{5} =\dfrac{2}{10} \ \mathrm{and} \ \dfrac{1}{2} =\dfrac{5}{10} \end{array}\\ & \\ \hline =\dfrac{p^{( 14/10)}}{\left( p^{3}\right)^{-1/5}} & \mathrm{Combine\ fractions.}\\ & \\ \hline =p^{7/5}\left( p^{3}\right)^{1/5} & \begin{array}{l} \mathrm{Reduce} \ \dfrac{14}{10} \ \mathrm{to} \ \dfrac{7}{5}.\\ \\ \mathrm{Apply\ the\ rule}\\ \dfrac{1}{a^{-n}} =a^{n} \end{array}\\ & \\ \hline =p^{7/5} \cdot p^{3/5} & \begin{array}{l} \mathrm{Apply\ the\ rule}\\ \left( a^{m}\right)^{n} =a^{m\cdot n} \end{array}\\ & \\ \hline =p^{7/5+3/5} & \begin{array}{l} \mathrm{Apply\ the\ rule}\\ a^{m} \cdot a^{n} =a^{m+n} \end{array}\\ & \\ \hline =p^{10/5} & \mathrm{Add\ fractional\ exponents}\\ & \\ \hline =p^{2} & \mathrm{Simplify}\\ \hline \end{array}$
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