College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.6 - Rational Exponents - R.6 Exercises - Page 58: 114

Answer

$27$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To simplify the given expression, $ 0.1^{3/2}\cdot90^{3/2} ,$ use the laws of exponents. $\bf{\text{Solution Details:}}$ Using the extended Power Rule of the laws of exponents which is given by $\left( x^my^n \right)^p=x^{mp}y^{np},$ the expression above is equivalent to \begin{array}{l}\require{cancel} (0.1\cdot90)^{3/2} \\\\= 9^{3/2} .\end{array} Using the definition of rational exponents which is given by $a^{\frac{m}{n}}=\sqrt[n]{a^m}=\left(\sqrt[n]{a}\right)^m,$ the expression above is equivalent to \begin{array}{l}\require{cancel} (\sqrt[]{9})^{3} \\\\= (3)^{3} \\\\= 27 .\end{array}
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