Answer
$3x\sqrt{2x}$
Work Step by Step
$\sqrt{6x} \cdot \sqrt{3x^{2}}$
By the product rule for square roots
$=\sqrt{6x \cdot 3x^{2}}$
$=\sqrt{18x^{3}}$
$=\sqrt{9\cdot x^{2} \cdot 2 \cdot x}$
$=\sqrt{9} \cdot \sqrt{x^{2}} \cdot \sqrt{2x}$
$=3x\sqrt{2x}$
