College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 48: 66

Answer

$\frac{1}{2}$

Work Step by Step

We know that $\sqrt[6] \frac{1}{64}=\frac{1}{2}$, because $\frac{1}{2}^{6}=\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}=\frac{1}{64}$.
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