Answer
$3\sqrt[3] 2$
Work Step by Step
$\sqrt[3] 9\times \sqrt[3] 6=\sqrt[3] (9\times6)=\sqrt[3] 54=\sqrt[3] (27\times2)=\sqrt[3] 27\times \sqrt[3] 2=3\sqrt[3] 2$
We know that $\sqrt[3] 27=3$, because $3^{3}=27$.
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 48: 71
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