College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 50: 118

Answer

See below.

Work Step by Step

I substitute in $v=0.9c$ in the given expression: Thus $R_a=R_f\sqrt{1-(\frac{v}{c})^2}=R_f\sqrt{1-(\frac{0.9c}{c})^2}=R_f\sqrt{1-(0.9)^2}=R_f\sqrt{1-0.81}=R_f\sqrt{0.19}\approx0.44R_f$ Thus the aging rate relative to someone's aging rate on Earth is $0.44$ Thus $44 $ weeks for me are $\frac{44}{0.44}=100$ weeks for my friend.
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