Answer
False
$8^{\frac{-1}{3}} = \frac{1}{2}$
Work Step by Step
By the definition of
$a^{\frac{-1}{n}} = \frac{1}{a^{\frac{1}{n}}} = \frac{1}{\sqrt[3]a}$ where $ a \ne 0$
$8^{\frac{-1}{3}} = \frac{1}{8^{\frac{1}{3}}}$
$= \frac{1}{\sqrt[3]8} = \frac{1}{2}$
