Answer
The statement does not make sense since the denominator was rationalized correctly.
Work Step by Step
To confirm adequate rationalization of the exercise, we solve in the following manner:
$$\frac{7\sqrt {2}}{\sqrt{6}}$$
= $\frac{7\sqrt {2}}{\sqrt{6}} \times \frac{\sqrt 6}{\sqrt 6}$
= $\frac{7\sqrt {2\times6}}{\sqrt{6^2}}$
=$\frac{7\sqrt {12}}{6}$
=$\frac{7\sqrt {2^2 \times 3}}{6}$
= $\frac{7\times2\sqrt {3}}{6}$
=$\frac{7\sqrt {3}}{3}$
