College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 51: 136

Answer

False. $\frac{\sqrt 20}{8} = \frac{\sqrt 5}{4}$

Work Step by Step

$\frac{\sqrt 20}{8} = \frac{\sqrt 4 \times \sqrt 5}{8}$ $= \frac{2 \times \sqrt 5}{8}$ $= \frac{1 \times \sqrt 5}{4}$ $= \frac{\sqrt 5}{4}$
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