College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 51: 138

Answer

$\sqrt (25x^{14}) = 5x^{7}$

Work Step by Step

Let a and b are co-efficient of x and power of x respectively. $\sqrt (ax^{b}) = 5x^{7}$ Squaring on both sides, $ax^{b} = (5x^{7})^{2}$ When a product is raised to a power, raise each factor to that power. $ax^{b} = 5^{2}x^{7 \times 2}$ $a x^{b} = 25 x^{14}$ a= 25 and b = 14 Substituting a and b in the given equation, we get $\sqrt (25x^{14}) = 5x^{7}$
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