College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.5 - Page 75: 103

Answer

(x+1) (2x + 1) (5x - 6)

Work Step by Step

The given polynomial = 10$x^{2}$(x+1) - 7x(x+1) - 6(x+1). Take (x+1) common from given expression. (x+1) (10$x^{2}$ - 7x - 6). Now do factor of (10$x^{2}$ - 7x - 6). 10$x^{2}$ - 12x + 5x - 6 = 2x(5x - 6) + 1(5x - 6) = (2x + 1) (5x - 6) 10$x^{2}$(x+1) - 7x(x+1) - 6(x+1) = (x+1) (2x + 1) (5x - 6)
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