College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Test - Page 91: 11

Answer

$\frac{x+3}{x-2}$

Work Step by Step

Factor the numerator and denominator using trial and error, and then cancel out common terms on the top and bottom. $\frac{x^2+2x-3}{x^2-3x+2}$ $\frac{(x+3)(x-1)}{(x-2)(x-1)}$ $\frac{x+3}{x-2}$
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