Answer
$\frac{(-3x-4)\sqrt[3]{x}}{\sqrt[3]{x-2}}$
Work Step by Step
$2x^{1/3}(x-2)^{2/3}-5x^{4/3}(x-2)^{-1/3}=x^{1/3}(x-2)^{-1/3}[2(x-2)-5x]=x^{1/3}(x-2)^{-1/3}(2x-4-5x)=x^{1/3}(x-2)^{-1/3}(-3x-4)=\frac{(-3x-4)\sqrt[3]{x}}{\sqrt[3]{x-2}}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises - Page 43: 59
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