Answer
$(x-3)(x^2+3x+9)$
Work Step by Step
RECALL:
A difference of two cubes can be factored using the formula
$A^3-B^3=(A-B)(A^2+AB+B^2)$
The given binomial can be written as:
$=x^3-3^3$
The binomial is a difference of two cubes.
Factor using the formula above with $A=x$ and $B=3$ to obtain:
$=(x-3)(x^2+(x)(3)+3^2)
\\=(x-3)(x^2+3x+9)$
