Answer
See below
Work Step by Step
Initial problem: $(\sin x)y'-y\cos x=\sin 2x$
The solution to this equation is:
$$y=2[\sin (x)+\sin(x)\ln(x)]$$
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 1 - First-Order Differential Equations - 1.6 First-Order Linear Differential Equations - Problems - Page 60: 35
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