Answer
See below
Work Step by Step
Since $A$ has igenvalues $\lambda=1,1,1$, it will have three Jordan canonical forms, such as:
$$\begin{bmatrix}
1 & 0 & 0\\
0 & 1 & 0 \\
0 & 0 & 1
\end{bmatrix}$$
$$\begin{bmatrix}
1 & 1 & 0\\
0 & 1 & 0 \\
0 & 0 & 1
\end{bmatrix}$$
$$\begin{bmatrix}
1 & 1 & 0\\
0 & 1 & 1 \\
0 & 0 & 1
\end{bmatrix}$$
