Answer
75 forms
Work Step by Step
A $11 \times 11$ matrix $A$ has $\lambda =2$ with multiplicity $4$, then there will be 5 possible Jordan block sizes.
A $11 \times 11$ matrix $A$ has $\lambda =6$ with multiplicity $4$, then there will be also 5 possible Jordan block sizes.
Then $\lambda =8$ has multiplicity $3$, so there will be 3 possible Jordan block sizes.
Hence, the number of Jordan canonical forms is: $5 \times 5 \times 3 =75$
