Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set - Page 28: 72

Answer

9

Work Step by Step

$10-[(4-5)^{2}+(12-14)]^{4}$ To simplify this expression, first perform the operations in parentheses. $10-[(-1)^{2}+(-2)]^{4}$ Next, perform the operations in brackets. $10-[(-1\times-1)+(-2)]^{4}=10-[1+(-2)]^{4}=10-[-1]^{4}$ Finally, perform the remaining operations. $10-(-1\times-1\times-1\times-1)=10-(1)=9$
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