Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set - Page 28: 77

Answer

$\frac{3(-2+1)}{5}$-$\frac{-7(2-4)}{1-(-2)}$ = $\frac{-79}{15}$

Work Step by Step

Directions: Simplify each expression. $\frac{3(-2+1)}{5}$-$\frac{-7(2-4)}{1-(-2)}$ $\frac{3(-1)}{5}$-$\frac{-7(-2)}{1-(-2)}$ Simplify inside parenthesis $\frac{-3}{5}$-$\frac{14}{3}$ Distribute the 3, -7, and -1 to the parenthesis, respectively $\frac{-9}{15}$-$\frac{70}{15}$ Multiply the numerator and denominator of the fractions by 3 and 5, respectively, in order to get common denominators $\frac{-79}{15}$ Subtract fractions to get final answer
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