Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set - Page 28: 78

Answer

$-2\frac{5}{28}$

Work Step by Step

We have $\frac{-1-2}{2(-3)+10} - \frac{2(-5)}{-1(8)+1}$ Solving $$\frac{-3}{-6+10} - \frac{-10}{-8+1}$$ $$\frac{-3}{4} - \frac{-10}{-7}$$ $$\frac{-3}{4} - \frac{10}{7}$$ $$\frac{-21-40}{28}$$ $$\frac{-61}{28} = -2\frac{5}{28}$$
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