Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set - Page 68: 42

Answer

length of the rectangular swimming pool is $ 120 \; feet $ and width of the rectangular swimming pool is $ 40 \; feet $ its dimensions are $ 40\; feet \; by\; 120\; feet $

Work Step by Step

Let $ l $ represents the length. and $ w $ represents the width. The rectangular swimming pool is three times as long as it is wide. In mathematical form. $ l=3w $ … (1) the perimeter of the rectangular swimming pool is $ P=2l+2w $. From the question $ P=320 \; feet $ plug into above equation. $ 320=2l+2w $ Substitute the value of $ l $ from equation (1). $ 320 = 2(3w)+2w $ $ 320 = 6w+2w $ $ 320 = 8w $ $ \frac{320}{8} = w $. $ 40 = w $ Substitute above value into equation (1). $ l=3(40) $ $ l=120 $.
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