Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set - Page 68: 60

Answer

$r^2=\dfrac{3V}{\pi{h}}$

Work Step by Step

Multiply 3 to both sides: $3\cdot V=3 \cdot \frac{1}{3}\pi{r^2}h \\3V=\pi{r^2}h$ Divide by $\pi{h}$ on both sides: $\dfrac{3V}{\pi{h}} = \dfrac{\pi{r^2}h}{\pi{h}} \\\dfrac{3V}{\pi{h}} = r^2 \\r^2=\dfrac{3V}{\pi{h}}$
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